Question

draw the graph of p(x)=x2-x-12​

Answer 1

Refer the attached figure.

Step-by-step explanation:

Given : Polynomial $p(x)=x^2-x-12$.

To find : The graph of the polynomial ?

Solution :

We plot the graph of polynomial on different value of x and y,

Since it is quadratic function it form a parabola.

The number of zeros are 2 and the zeros are the points where the graph of the polynomial intersects the x-axis.

Zeros are : (-3,0) and (4,0)

On y-axis the point is (0,-12).

The vertices of the parabola is (0.5,-12.25).

Refer the attached figure below.

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Answer 2

Given : p(x)=x²-x-12​

To Find : Solve

Solution:

p(x)=x²-x-12

p(x) = x² - 4x + 3x - 12

=> p(x) = x(x - 4) + 3(x - 4)

=>  p(x) = (x + 3)(x - 4)

x           p(x) =x²-x-12

5            8

4            0

3            -6

2            -10

1             -12

0.5         -12.25

0            -12

-1            -10

-2           -6

-3            0

-4            8

roots/Zeros

x = - 3

x = 4

Minimum value  - 12.25  at  x = 0.5

Graph symmetric about x = 0.5

 

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