draw the graph of polynomial x^2+5x+6 find zeros and justify your answer
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Answered by
5
x²+5x+6
x²+2x+3x+6
x(x+2)+3(x+2)
(x+2)(x+3)
(x+2)=0
x=-2
(x+3)=0
x=-3
roots of the equation are -2 & -3
x²+5x+6
sum of roots=-2-3
=-5
-(coefficient of x)/coefficient of x²=-b/a
=-5/1
=-5
so,
sum of roots=-(coefficient of x)/coeff.of x²
now,
product of roots=-2×(-3)
=6
Constant term/coefficient of x²=c/a
=6/1
=6
So,
product of roots=constant term/coeff.ofx²
hence,verified..
@Altaf
x²+2x+3x+6
x(x+2)+3(x+2)
(x+2)(x+3)
(x+2)=0
x=-2
(x+3)=0
x=-3
roots of the equation are -2 & -3
x²+5x+6
sum of roots=-2-3
=-5
-(coefficient of x)/coefficient of x²=-b/a
=-5/1
=-5
so,
sum of roots=-(coefficient of x)/coeff.of x²
now,
product of roots=-2×(-3)
=6
Constant term/coefficient of x²=c/a
=6/1
=6
So,
product of roots=constant term/coeff.ofx²
hence,verified..
@Altaf
Answered by
0
(x+2)(x+3)=0
Step-by-step explanation:
p(x)=x2+5x+6
let p(x)=0
x2+5x+6=0
(x+2)(x+3)=0
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