Draw the graph of quadratic equation y2=x2-3x-4
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Answer:
If x = 0, ⇒ y= 02 - 3(0) - 4 = - 4 If x = 1 ⇒ y= 12 - 3(1) - 4 = - 4 = 1 - 3 - 4 = - 6 If x = -1 ⇒ y = y= (-1)2 - 3(-1) - 4 = 1+3 - 4 = 0 If x = 4 ⇒ y = (-1)2 - 3(4) - 4 = 16 - 12 - 4 = 0 The coordinate points of the given equation are
x
0,1,-1,4
y
-4,-6,0,0
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Step-by-step explanation:
put x=0
y2=(0)2-3*0-4
y2=-4
y=√-4
y=+-2
put x=-1
y2= (-1) 2-3*-1-4
y2=4-4
y=0
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