Question

draw the graph of quadric polynomial -x²-2x+3​

Answer 1

Step-by-step explanation:

Let y =f(x) or, y=3−2x−x

2

.

Let us list a few values of y=3−2x−x

2

corresponding to a few values of x as follows

x −5 −4 −3 −2 −1 0 1 2 3/4

y=3−2x−x

2

−12 −5 0 3 4 3 0 −5 −12/−21

Thus, the. following points lie on the graph of the polynomial y=3−2x−x

2

(−5,−12),(−4,−5),(−3,0),(−2,3),(−1,4),(0,3),(1,0),(2,−5),(3,−12) and (4,−21).

Let plot these points on a graph paper and draw a smooth free hand curve passing through these points to obtain the graphs of y=3−2x−x

2

. The curve thus obtained represents a parabola, as shown in figure. The highest point P (−1,3), is called a maximum points, is the vertex of the parabola. Vertical line through P is the axis of the parabola. Clearly, parabola is symmetric about the axis.

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