Math, asked by ansulibasumatary397, 7 months ago

draw the graph of signum function f:R->R defined by f(x)={1,if x>0}, {0,if x=0}
{-1, if x <0}​

Answers

Answered by harshilvetri
2

Answer:

Please mark me as BRAIN-LIEST

Step-by-step explanation:

: R → R, given by  

f(x)={1,if x>0}, {0,if x=0}

{-1, if x <0}​

It is seen that f(1) = f(2) = 1, but 1 ≠ 2.

∴f is not one-one.

Now, as f(x) takes only 3 values (1, 0, or - 1) for the element - 2 in co-domain R, there does not exist any x in domain R such that f(x) = - 2.

∴ f is not onto.

Hence, the signum function is neither one-one nor onto.

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