Draw the graph of the equation 2(x+3)-3(1+y)=0 also find the point where the line meets x-axis
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2[x+3]-3[1+y]=0
2x+6-3+3y=0
2x-3y+6-3=0
y-3=0
y=3+0
y=3
the point will meet on positive x-axis
2x+6-3+3y=0
2x-3y+6-3=0
y-3=0
y=3+0
y=3
the point will meet on positive x-axis
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