draw the graph of the equation 2x+3y=12 whose y-coordinate is 3
Answers
Answer:
2x + 3y = 12
2x = 12 - 3y
x = 12 - 3y / 2
Putting y = 2 we get x = 12 - 3 x 2 / 2 = 3
Putting y = -4 we get x = 12 - 3 x 4 / 2 = 0
Thus, (3,0) and (0,4) are the two points on the line 2x+3y=12
Graph is in the attachment(It is quite blurred, nevermind)
To find coordinates on the points when y = 3, draw a line parallel to x - axis passing through (0,3). This line meets the graph of 2x+3y=12 at a point p from which a line parallel to y - axis is to be drawn which crosses x - axis at X=x = 3/2
So the coordinates of the required points are (3/2, 3)
To find coordinates on the points when x = -3, draw a line parallel to y - axis passing through (-3, 0). This line meets the graph of 2x+3y=12 at a point p from which a line parallel to x - axis is to be drawn which crosses y - axis at y = 6
So the coordinates of the required points are (-3, 6)
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Step-by-step explanation:
Answer:
2x + 3y = 12
2x = 12 - 3y
x = 12 - 3y / 2
Putting y = 2 we get x = 12 - 3 x 2 / 2 = 3
Putting y = -4 we get x = 12 - 3 x 4 / 2 = 0
Thus, (3,0) and (0,4) are the two points on the line 2x+3y=12
Graph is in the attachment(It is quite blurred, nevermind)
To find coordinates on the points when y = 3, draw a line parallel to x - axis passing through (0,3). This line meets the graph of 2x+3y=12 at a point p from which a line parallel to y - axis is to be drawn which crosses x - axis at X=x = 3/2
So the coordinates of the required points are (3/2, 3)
To find coordinates on the points when x = -3, draw a line parallel to y - axis passing through (-3, 0). This line meets the graph of 2x+3y=12 at a point p from which a line parallel to x - axis is to be drawn which crosses y - axis at y = 6
So the coordinates of the required points are (-3, 6)
MARK AS BRAINLIEST
PLZ FOLLOW ME
Step-by-step explanation:
