Draw the graph of the equation 2x- y=3 and 3x+2y=1 Find the point of intersection of these graphs
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Answer:
point of intersection is (1,-1)
Step-by-step explanation:
3x+2y=1 ................(eqn 1)
2x - y = 3
2x - 3 = y ……….…...(eqn 2)
substitute (eqn 2) in (eqn I),
3x+2y= 1
3x+2(2x-3)=1
3x+4x-6=1
3x+4x-6-1=0
7x-7=0
7x= 7
x= 1 ...........(eqn3)
substitute (eqn3) in (eqn2)
2x-3= y
2(1)-3 = y
2-3= y
y= -1 ...........(eqn 4)
therefore, the point of intersection is (1,-1)
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