Draw the graph of the equation x=2, x=5 and 2x-y=4. Also find the area of the quadrilateral formed by these lines and the x axis.
Answers
Step-by-step explanation:
Given:
x = 3 and 5
\begin{gathered}\textsf{Putting \: the \: values \: of \: x \: in \:2x - y - 4 = 0 } \\ \\ \text{Putting \: x = 3}\end{gathered}
Putting the values of x in 2x - y - 4 = 0
Putting x = 3
2x – y – 4 = 0
arrowarrow 2×3 – y – 4 = 0
arrowarrow 6 – y – 4 = 0
arrowarrow –y = –2
arrowarrow y = 2
\boxed{ \textbf{y = 2}}
y = 2
\text{Putting \: x = 5}Putting x = 5
2x – y – 4 = 0
arrowarrow 2×5 – y – 4 = 0
arrowarrow 10 – y – 4 = 0
arrowarrow –y = –6
arrowarrow y = 6
\boxed{ \textbf{y = 6}}
y = 6
\text{area \: of \: formed \: quadrilateral}area of formed quadrilateral
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ABCD is a square \text{as shown in graph...}as shown in graph...
Area of square = (side)²
arrowarrow A = 2 × 2
arrowarrow A = 4 cm²
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Area of triangle = 1/2 × b × h
arrowarrow A = 1/2 × 2 × 4
arrowarrow A = 4 cm²
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Area of quadrilateral = Sum of area of square and triangle .
arrowarrow A = 4 cm² + 4 cm²
arrowarrow A = 8 cm²
\boxed{ \text{Area of quadrilateral = 8 sq. cm}}
Area of quadrilateral = 8 sq. cm
