draw the graph of the following pair of liner equation in two variable 2x-3y=5 and 3x+4y=-1
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Solution:
2x + 5y = 12
We have,
x + y = 3
When y = 0 we have x = 3
When x = 0 we have y = 3
Thus we have the following table giving points on the line x + y = 3
X 0 3
Y 3 0
Now, 2 + 5y = 12
When x = 1, we have
Thus we have the following table giving points on the line 2x + 5y = 12
X 1 -4
Y 2 4
Graph of the equation x + y = 3 and 2x + 5y = 12 is
Graph of the equation
Clearly two lines intersect at a point P (1, 2)
Hence x = 1 and y = 2
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