Question

Draw the graph of the linear equation 2x + 3y = 12. At what points, the graph of the equation
cuts the x-axis and the y-axis?​

Answer 1

Answer:

Step-by-step explanation:

We know that, the coordinates of any point on x-axis are of the form (x, 0)

where, y = 0

similarly, coordinates of any point on y-axis are (0,y) and x= 0

Therefore, to find the intersection of on x-axis we take y = 0

i.e. 2x + 3y = 12

2x + 3(0) = 12

2x = 12

x = 12/2 = 6

So, the line cuts the x-axis at (6,0).

Similarly, taking x = 0 to find the point where the line cuts the y-axis

i.e. 2(0) + 3y = 12

3y = 12

y = 12/3 = 4

Thus, the line cuts the y-axis at (0,4).

Therefore, the line cuts the x-axis at (6,0) and y-axis at (0,4).