Math, asked by khunger, 1 year ago

draw the graph of the linear equation 2x-y+1=0.from your graph find the value of hand k if the graph passes through the point (h,4)and (1/2,k)

Answers

Answered by LaziestBoredBoy
29
please see attachment
Attachments:

khunger: thanks alot
khunger: can u tell it's graph also??pls
LaziestBoredBoy: oo
LaziestBoredBoy: ol
LaziestBoredBoy: ok
khunger: thanks
khunger: hey i didn't get the graph??
khunger: pls send it's urgent
khunger: do u sure that this graph is right??
Answered by JinKazama1
51
Final Answer : h = 3/2 , k = 2

Steps:
1) DRAWING Graph :
We will find at least points on equation 2x-y +1=0
When x = 0, y = 1
When y = 0 , x = -0.5
Join these points to get the graph of equation :
2x- y + 1 =0,
That is, straight line.

2) If Graph passes through the point (h, 4) , then x = h, y = 5
So,
2x - y +  1 = 0 \\  =  > 2h - 4 + 1 = 0 \\  =  > 2h - 3 = 0 \\  =  > h =  \frac{3}{2}

3) If graph passes through (1/2,k) ,then
x = 1/2 , y = k
So,
2x -  y+ 1 = 0 \\  =  > 2( \frac{1}{2} )  - k + 1 = 0 \\  =  >1 - k + 1 = 0 \\  =  > k = 2
Hence,
 \boxed   {h =  \frac{3}{2}  \: and \: k = 2}
Attachments:
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