The width is 2/3 of the length.The perimeter is 40.Find its dimensions
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Let the length be x.
Given that width is (2/3) of length.
= > (2/3) * x.
= > (2x/3)
Given that perimeter is 40.
We know that perimeter = 2(l + b).
= > 2(l + b) = 40
= > 2(x + 2x/3) = 40
= > x + 2x/3 = 20
= > 5x/3 = 20
= > 5x = 60
= > x = 12.
Now,
= > 2x/3
= > 2(12)/3
= > 24/3
= > 8.
Therefore the length = 12cm and width = 8cm.
Hope this helps!
Given that width is (2/3) of length.
= > (2/3) * x.
= > (2x/3)
Given that perimeter is 40.
We know that perimeter = 2(l + b).
= > 2(l + b) = 40
= > 2(x + 2x/3) = 40
= > x + 2x/3 = 20
= > 5x/3 = 20
= > 5x = 60
= > x = 12.
Now,
= > 2x/3
= > 2(12)/3
= > 24/3
= > 8.
Therefore the length = 12cm and width = 8cm.
Hope this helps!
siddhartharao77:
:-)
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