draw the graph of the linear equation 2x+y=3
Answers
Answer:
Pick some values for
x
, and use the equation to find what
y
must be for each of those
x
's.
For example, if
x
is 0, then we have:
2
x
+
y
=
3
⇒
2
(
0
)
+
y
=
3
⇒
0
+
y
=
3
⇒
y
=
3
So when
x
=
0
, we have
y
=
3
. Meaning the point
(
x
,
y
)
=
(
0
,
3
)
is a solution to
2
x
+
y
=
3
, and so our graph of the equation will pass through
(
0
,
3
)
.
We can get a few more points:
If
x
=
1
, then
2
x
+
y
=
3
⇒
2
(
1
)
+
y
=
3
⇒
2
+
y
=
3
⇒
y
=
1
So
(
x
,
y
)
=
(
1
,
1
)
is also on our graph.
Similarly, if
x
=
2
, then we get
y
=
–
1
, giving us the point
(
x
,
y
)
=
(
2
,
–
1
)
.
We then take the points we've computed,
(
0
,
3
)
,
(
1
,
1
)
,
(
2
,
–
1
)
, and plot them on a graph:
graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)=0 [-10, 10, -5, 5]}
Last, since we know this equation is linear, we just need to connect the dots with a line:
graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)(2x+y-3)=0 [-10, 10, -5, 5]}
And we're done!
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