Question

Draw the graph of the linear equations 3x+7y=21. Find the area bounded by the line with coordinate axes.​

Answer 1

Answer:

Refer the attached graph.

Step-by-step explanation:

To find : Draw the graph of the linear equation 3x-7y=213x−7y=21 ?

Solution :

We plot the linear equation by two intercept points.

The x-intercept is when y=0,

Put y=0 in the equation,

3x-7(0)=213x−7(0)=21

3x=213x=21

x=\frac{21}{3}x=

3

21

x=7x=7

The point is (7,0).

The y-intercept is when x=0,

Put x=0 in the equation,

3(0)-7y=213(0)−7y=21

-7y=21−7y=21

y=-\frac{21}{7}y=−

7

21

y=-3y=−3

The point is (0,-3).

We plot the points and draw a straight line.

Refer the attached graph below.

#Learn more

Draw graph of this equation :-

→ y = |2x - 3| .