Draw the graph of the polynomial p(x) = 6- x - x ^2 find the zeroes and justify your answer.
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p(x) = 6 - x - x²
0 = x² + x - 6
x² + 3x - 2x - 6 = 0
x ( x + 3 ) - 2 ( x + 3 ) = 0
( x + 3 ) ( x - 2 ) = 0
x + 3 = 0 or x - 2 = 0
x = - 3 or x = 2
hence , zeroes are -3 and 2
I hope this will be help you
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