Draw the graph of y=x²-x-12, find the zeroe of y=x²-x-12?
Answers
Answer:
The given quadratic equation is x
2
+x−12=0.
Let y=x
2
+x−12, when we substitute different values of x in the equation y=x
2
+x−12 then value of y changes accordingly.
When x=0 then
y=(0)
2
+0−12=0+0−12=−12
The point is (0,−12)
When x=3 then
y=(3)
2
+3−12=9+3−12=0
The point is (3,0)
When x=−4 then
y=(−4)
2
−4−12=16−4−12=0
The point is (−4,0)
Therefore, the coordinates are (0,−12), (3,0) and (−4,0) and the graph of the quadratic equation y=x
2
+x−12 is as shown above.
Hence, from above graph, we get that x=−4 or x=3.
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Answer:
4 or - 3 are the zeroes of polynomial x²-x-12 .
Step-by-step explanation:
y=x²-x-12
=x²-4x+3x-12
=(x²-4x)+(3x-12)
=x(x-4)+3(x-4)
=(x-4) (x+3)
For zeroes of polynomial y.
(x-4)(x+3)=0
Therefore the zeroes are
x=4 or x= -3