Question

Draw the graph representing the equation 4x + 3y = 21 and 3y = 4x + 24
on the same graph paper. Write the co-ordenates of the point of intersection
of there lines and find the area of triangle formed by these line and the
x-axis.​

Answer 1

Step-by-step explanation:

For 4x + 3y = 24,

(x , y) = (0, 8) =(3, 4) =(6, 0)

Put, x = 0, we get y = 8

Put x = 3 we get y = 4 and

put x = 6 we get y = 0

For 3y = 4x + 24 ,

(x , y)=(-6, 0)=(-3, 4)=(0,8)

Put x = - 6 we get y = 0

Put x = -3 we get y = 4

Put x = 0 we get y = 8

Now, we have ∆ ABC,

With Base BC = 12 units, Height AO = 8 units,

We know that, A (∆ ABC) = ½ (Base) (Height)

∴ A(∆ ABC) = ½ (BC)(AO)

∴ A(∆ ABC) = ½ (12)(8)

∴ A(∆ ABC) = 6 × 8

∴ A(∆ ABC) = 48 sq. units