Question

Draw the graph showing the intensity distribution of fringes due to diffraction at single slit

Answer 1

Answer:

Intensity of bright fringe due to single slit diffraction will decrease on the screen as we move away from central bright fringe

Explanation:

As we know that the position of minimum intensity on screen due to single slit is given as

$a sin\theta = n\lambda$

here we know that

a = width of single slit

$\theta$ = angular position of minimum

Now intensity of the fringe on the screen is given as

$I = I_o (\frac{sin\frac{\delta}{2}}{\frac{\delta}{2}})^2$

here we know that

$\delta = \frac{2\pi a sin\theta}{\lambda}$

so here the pattern of intensity on screen is given as

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Topic : diffraction due to single slit

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