Draw the graphs of the given polynomial and find the zeroes. Justify the answers (ii) p(x) = x² - 6x + 9 (iv) p(x) = x + 3x - 4
Answers
Answered by
0
Answer:
(ii) x²- 6x + 9
= x² + 3x +3x + 9 =0
=x(x + 3) + 3(x + 3)=0
= (x + 3) (x + 3) =0
= x = -3,-3
the zeroes of this polynomial is -3,-3.
(iv) x + 3x - 4
= x² + 4x - x - 4 = 0
= x(x + 4) - 1 (x + 4) = 0
= (x + 4) (x - 1) = 0
= x = -4,+1
the zeroes of this polynomial is -4,+1
Similar questions