Question

draw the line passing through (4,3)and (3,4).Find the coordinates of at which this line meets the x - axis and y- axis.
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Answer 1

The line meets the x-axis at (7, 0) and the y-axis at (0, 7).

Step-by-step explanation:

Given, the required line passes through the points (4, 3) and (3, 4).

Then the equation of the line is

$\quad\dfrac{y-4}{4-3}=\dfrac{x-3}{3-4}$

⇒ $\dfrac{y-4}{1}=\dfrac{x-3}{-1}$

⇒ y - 4 = - (x - 3)

⇒ y - 4 = - x + 3

⇒ x + y = 7

• When this line meets the x-axis, we take y = 0. Then, x + 0 = 7 ⇒ x = 7. So, the required point is (7, 0).
• When the line meets the y-axis, we take x = 0. Then, 0 + y = 7 ⇒ y = 7. So, the required point is (0, 7).