Math, asked by puskarshaw, 1 year ago

the length of a rectangular playground is thrice its breadth if the perimeter of the playground is 56 metre find its dimensional​

Answers

Answered by Sauron
55

\textsf{\underline{\underline{Answer :-}}}

The Length is 21 m and Breadth is 7 m

\textsf{\underline{\underline{Explanation :-}}}

Given :

Length of the Rectangle = Thrice of the Breadth

Perimeter of Rectangle = 56 m

To find :

The Length and Breadth of the Rectangle

Solution :

Consider the Breadth of the Rectangle as x

Consider the Length as 3x

\star As we know :-

\boxed{\sf{Perimeter = 2(Breadth+ Length)}}

\sf{\implies}2(x + 3x)= 56

\sf{\implies}2x + 6x = 56

\sf{\implies}8x = 56

\sf{\implies}x =  \dfrac{56}{8}

\sf{\implies}x = 7

Breadth = 7 m

Value of 3x

\sf{\implies} 3 × 7

\sf{\implies} 21

Length = 21 m

\therefore The Length is 21 m and Breadth is 7 m

\textsf{\underline{\underline{Verification :-}}}

\sf{\implies}2(7 + 21) = 56

\sf{\implies}14 + 42 = 56

\sf{\implies}56 = 56

\therefore The Length is 21 m and Breadth is 7 m


Anonymous: At the place of length you've taken 'x' instead of '3x' and at the place of breadth you've taken '3x' instead of 'x'. Just correct it ☺️
Answered by Anonymous
32
\sf{\underline{\underline{Given:}}}

Length of the playground = 3 (Breadth)

Perimeter of the playground = 56 m

Playground (shape) \implies Rectangular


\sf{\underline{\underline{Now:}}}

Let the breadth of the rectangle be x.

Let the length of the rectangle be 3x.


\sf{Formula\:for\:Perimeter\:of\:rectangle:}

\boxed{Perimeter = 2(Length + Breadth)}


\sf{\underline{\underline{Here:}}}

\sf{Perimeter} = 56 m

\sf{Length} = 3x

\sf{Breadth} = x

Substituting these values in the above formula we get,

\sf{Perimeter = 2(Length + Breadth)}

\sf{56= 2(3x + x)}

\sf{56 = 6x + 2x}

\sf{56 = 8x}

\sf{ \frac{56}{8} = x}

\sf{7 = x}

\sf{\underline{\underline {Therefore:}}} \boxed{x = 7}

Now, we know that, the breadth of the playground is 7 m.


\sf{\underline{\underline{We\:have:}}}

\sf{Length = 3x}

Substituting the value of x, we get,

\sf{Length = 3x}

\sf{Length = 3 \times 7}

\sf{Length=} \boxed{ 21 \: m}


\sf{\underline{\underline{Therefore:}}}

The length of the playground is 21 m and breadth is 7 m.

Anonymous: perfection on The peak ☺️❤️☺️
Anonymous: thanks for appreciation brother ☺️ it means a lot for me ☺️
Anonymous: ☺️☺️
Binand: Thanks
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