Question

draw the molecular energy level diagram for O2^+ molecule and find out the bond order of the species

Answer 1

The bond order of O2+ is 2.5.

• 02+ contains 15 electrons.
• Electronic configuration of 02+ according to MOT = ¶1s²¶*1s2 ¶2s² ¶*2s² ¶2pz² п2рx² = п2ру² п*2рx1 = п*2рy.
• O2+ is paramagnetic due to the presence of one unpaired electron in anti-bonding orbital π*2px.
• Bond order is calculated by
• $\frac{nb - na}{2}$
• Here, nb is several electrons in the bonding molecular orbit while na is the antibonding molecular orbit.
• Now,
• $\frac{10 - 5}{2} = \frac{5}{2} = 2.5$

#SPJ2