Question

Draw the ray diagram to represent an object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 30cm.

Answer 1

GIVEN :-

$= > u = - 10 \: cm\\ \\ = > f = - \frac{R}{2} = - \frac{30}{2} = - 15 \: cm \\ \\ USING \: \: FORMULA \\ \\ = > \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\ \\ = > \frac{1}{ - 15} = \frac{1}{v} + \frac{1}{ - 10} \\ \\ = > \frac{1}{v} = \frac{1}{15} - \frac{1}{10} = \frac{2 - 3}{30} \\ \\ = > \frac{1}{v} = - \frac{1}{30} \\ \\ = > v = - 30 \: cm \\ \\ HENCE \\ \\ IMAGE \: \: IS \: \: THE \: \: \\ "VIRTUAL" \: \: "ERECT" \: \: "MAGNIFIED \: \: 3 \: \: TIMES"$
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_-_-_-_☆$BE \: \: \: \: BRAINLY☆_-_-_-_$

Answer 2

@ Hey friends.....@
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Have a look for your answer in the above pic.---->

Hope it will help you!!
Thanks!!!
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