Question

An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius
of curvature 30cm, Find the nature, position and size of the image.

Answer 1

GIVEN

$= > u = - 10 \: cm \\ \\ = > f = - \frac{r}{2} = - \frac{30}{2} = - 15 \: cm \\ \\ using \: \: formula \\ \\ = > \frac{1}{f} = \frac{1}{v} \: + \: \frac{1}{u} \\ \\ = > \frac{1}{ - 15} = \frac{1}{v} + \frac{1}{ - 10} \\ \\ = > \frac{1}{v} = \frac{1}{15} - \frac{1}{10} \\ \\ = > \frac{1}{v} = \frac{3 - 2}{30} = \frac{1}{30 } \\ \\ = > v = + 30 \: cm$
HENCE,

Image is VIRTUAL, ERECT, MAGNIFIED 3 times.

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_-_-_-_☆$BE \: \: \: \: BRAINLY$☆_-_-_-_

Answer 2

Explanation:

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