Question

Draw the rough graph of the quadratic equation ax2+bx+c = 0;
when b2 - 4ac > 0
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Answer 1

Step-by-step explanation:

heres ur and.

ans. hope it helps you

Answer 2

ax² + bx + c = 0, is a quadratic equation which vertex is (-b/2a, -D/4a). where D is discriminant.i.e., D = b² - 4ac.

there are three situations possible for quadratic equation

1. when D = b² - 4ac = 0 , it means quadratic touch at a point on x-axis. hence, roots of quadratic equation will be equal.
2. when D = b² - 4ac < 0, it means quadratic equation doesn't have real roots. because it neither touches nor intersects the x-axis.
3. when D = b² - 4ac > 0, it means quadratic equation have real roots and both are distinct. graph of quadratic equation intersects two two points on the x-axis.

here we have to draw the last situation (situation no 3). vertex = (-b/2a, D/4a)

and roots are α and β

so, graph would be as shown in figure.