Chemistry, asked by AtithiRoy, 1 year ago

draw the structure of the following IUPAC compound:
1
a. 2, 8-Dimetyl-3, 6-decadiene
b. 4-Ethyl-2, 6-dimethyl-dec-4-ene
c. 1,3,5,7 octateraene
d. 4-Nitroso-N-methylbenzenamine
e. Benzene 1, 4-dicarboxylic acid
f. 1-Phenylpropanone

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Answered by Anjali1313
26
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Answered by IlaMends
3

Explanation:

a. 2, 8-Dimetyl-3, 6-decadiene  

Long chain of 10 carbon atoms with two double bonds present between third & forth carbon atom and sixth & seventh carbon atom.

b. 4-Ethyl-2, 6-dimethyl-dec-4-ene

Long chain of 10 carbon atoms with 1 double bond present between forth & fifth carbon atom.

c. 1,3,5,7 octateraene

Long chain of 8 carbon atoms with 4 double bonds present:

  • between first & second carbon atom.
  • between third & forth carbon atom.
  • between fifth & sixth carbon atom.
  • between seventh & eighth carbon atom.

d. 4-Nitroso-N-methylbenzenamine

(-NO) group is on 4th position of the benzene ring with (NH-CH_3) on the ring

e. Benzene 1, 4-dicarboxylic acid

(-COOH) group on forth position of the benzene ring of benzoic caid.

f. 1-Phenylpropanone

Benzene ring present on an one of side of the propanone.

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