Draw triangle ABC with side BC= 6 cm, angle B=45 degree and Angle A = 100 degree construct triangle PBQ whose sides are 7/4 times the corresponding side of triangle ABC
Answers
Constructed ΔABC with side BC= 6 cm, angle B=45° and Angle A = 100° ΔPBQ is 7/4 times ΔABC
Step-by-step explanation:
∠B = 45°
∠A = 100°
∠A + ∠B + ∠C = 180°
=> 100° + 45° + ∠C = 180°
=> ∠C = 35°
Step 1 : Draw a line segment BC = 6 cm
Step 2 : Draw an angle of 45° at B on BC using Protector
Step 3 : Draw an angle of 35° at C on BC using Protector such that it intersect angle drawn in step 2 at A
Δ ABC is constructed
to Construct Δ PBQ whose sides are 7/4 times the corresponding side of ΔABC
Draw an acute angle at BC
Using compass take one by one 7 equal distant point
join 4th point with C
Draw a line parallel to the line passing through 7th point and cutting Extended BC at Q
Extend BA
Draw a line parallel to AC passing through Q & cutting Extended BA at P
ΔPBQ is 7/4 times ΔABC
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