Math, asked by pradithyan2, 6 months ago

draw triangles with two sides 8cm and 6 cm and 12 sq cm what if the area is to be 24 sq cm​

Answers

Answered by prabirsarkar1464
0

Answer:

Answer

Answer5.0/5

Area of a triangle = 1/2.a.c.sinB

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinB

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm and

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear....

Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear....pls mark as brainliest

Step-by-step explanation:

I reall hope it is helping u so plz follow me

Similar questions