draw triangles with two sides 8cm and 6 cm and 12 sq cm what if the area is to be 24 sq cm
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Area of a triangle = 1/2.a.c.sinB
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinB
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm and
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear....
Area of a triangle = 1/2.a.c.sinB12 cm^2= 1/2.8 cm.6 cm.sinB.or. sinB=12/24 = 1/2or. B= 30° or 150°.Thus , only two triangles are possible to draw.(1) sides a=8 cm , c=6 cm and angle between them B=30°.(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.Again , area of the triangle = 1/2.a.c.sinB24 cm^2= 1/2.8 cm.6 cm.sinB24 = 24.sinBor. sinB=24/24= 1or B= 90°.Thus , only a right angled triangle in which a=8 cm ,c =6 cm andangle between them B= 90°. Answer.....hope this hepls uh dear....pls mark as brainliest
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