Math, asked by brainlyking02455, 5 months ago

Draw Trigonometry Table by LaTeX......​

Answers

Answered by ItzVenomKingXx
46

\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}

Answered by BrainlyFlash
18

{\huge{\star{\underbrace{\tt{\red{Answer}}}}}}{\huge{\star}}

\documentclass{article}

\usepackage[nomessages]{fp}

\usepackage[table]{xcolor}

\usepackage{calculator}

\usepackage{forloop}

\usepackage{supertabular}

\usepackage{longtable}

\usepackage{fullpage}

\begin{document}

\newcounter{theangle}

\tablefirsthead{

\cline{2-4}

\rowcolor{white}

\multicolumn{1}{c|}{ } &

\cos \theta & \sin \theta & \tan \theta &

\multicolumn{1}{c}{ } \\

\hline

}

\tablehead{

\rowcolor{white}

\multicolumn{5}{c}{Table continued \ldots}\\

\cline{2-4}

\rowcolor{white}

\multicolumn{1}{c|}{ } &

\cos \theta & \sin \theta & \tan \theta &

\multicolumn{1}{c}{ } \\

\hline

}

\tablelasttail{

\rowcolor{white}

\multicolumn{1}{c|}{ } &

\cos \theta & \sin \theta & \tan \theta &

\multicolumn{1}{c}{ }\\

\cline{2-4}

}

\tabletail{

\hline

\rowcolor{white}

\multicolumn{1}{c|}{ } &

\cos \theta & \sin \theta & \tan \theta &

\multicolumn{1}{c}{ } \\

\cline{2-4}

\rowcolor{white}

\multicolumn{5}{c}{Continued on next page \ldots}\\

}

\rowcolors{2}{gray!50}{white}

\begin{center}

\begin{supertabular}{*5{|>{$}c<{$}}|}

\forloop{theangle}{0}{\value{theangle} < 360}{

\arabic{theangle}^\circ &

\DEGREESCOS{\value{theangle}}{\solx} \solx &

\DEGREESSIN{\value{theangle}}{\solx} \solx &

\DEGREESTAN{\value{theangle}}{\solx} \solx &

\arabic{theangle}^\circ\\

\addtocounter{theangle}{4}

}

\end{supertabular}

\end{center}

\end{document}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

\Large\mathcal{\fcolorbox{lime}{black}{\red{Hope it's help  ⚓⚓}}}

\large\mathcal{\fcolorbox{yellow}{teal}{\orange{Please mark me as brainliest (. ❛ ᴗ ❛.)}}}

Similar questions