The number of electrons that travel through the given resistor 20 ohms in the circuit in one second is ...
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We have a relation between charge and current as
Charge=Current×time i.e Q=i×t.
Now we have current =10amp & time=1sec from given data.
Therefore charge Q=10×1=10 coulombs.
Again we have a relation between charge and no of electrons
I.e no of electrons= total charge/1.6×10^-19.
So, no of electrons=( 10C/1.6×10^-19 )=6.25×10^19 electrons.
Therefor, 6.25×10^19 electrons will flow through a copper wire carrying 10amps current for 1sec.
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