Question

Drive the third equation of motion by graphical method

Answer 1

The distance covered by an object in a given time is-

S(distance) =area of trapezium OABC

S=1/2×height×(sum of parallel sides)

S=1/2×OC×(OA+CB)

S=1/2×t×(u+v)

S=1/2×v-u/a×(v+u)

S=(v-u)(v+u)/2a

2aS=v square- u square

v square - u square=2aS