drive zero order reaction and first order reaction
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If the number of enzyme molecules is limited in relation to substrate molecules, then the reaction may appear to be zero-order. If B is present in great excess, then the reaction will appear to be zero order in B (and first order overall). This commonly happens when B is also the solvent that the reaction occurs in.
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Consider a zero order reaction
R→P
Rate =dt−d[R]=k[R]o
dt−d[R]=k[R]o
dt−d[R]=k
d[R]=−k⋅dt
Integrating on both sides
[R]=−kt+I (1)
k=t[R]o−[R]
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