driver applies a break from Singh traffic signal 400 metres ahead at the time of applying the brakes vehicle was moving with 15 metre per second hand reading with 0.3 metre per second squared the distance of vehicle after 1 minutes from the traffic light is
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What is hand reading
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from the unit, hand reading is acceleration. Or more clearly, it is negative acceleration since breaks are being applied
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u = 15m/s
a = -0.3 m/s²
t = 60s
v = u + at = 15 - 60*0.3 = 15 - 18 = -3m/s
but the minimum v = 0
So the vehicle will stop at time t = (u-v)/a = 15/0.3 = 45s
s = (v²-u²)/2a = (0 - 225)/0.6 = 375m
initially it was at distance = 400m
travelled = 375m
final distance = 400 - 375 = 25m
So distance from traffic light after 1 minute is 25m
a = -0.3 m/s²
t = 60s
v = u + at = 15 - 60*0.3 = 15 - 18 = -3m/s
but the minimum v = 0
So the vehicle will stop at time t = (u-v)/a = 15/0.3 = 45s
s = (v²-u²)/2a = (0 - 225)/0.6 = 375m
initially it was at distance = 400m
travelled = 375m
final distance = 400 - 375 = 25m
So distance from traffic light after 1 minute is 25m
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