Drops are falling at regular intervals of time from the roof of a building 16 m high. If the first drop reaches the ground at the instant the fifth drop start falling, find the heights of the various drops at the instant the first drop reaches the ground ?
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Height of the first drop = of course 0
Height of the second drop = 4 m
Height of the third drop = 8 m
Height of the fourth drop = 12 m
Height of the fifth drop = 16 m
The above given heights are from the ground.
See....the case is....when the first drop starts falling, the fifth drop has reached the ground.......implies that there are 4 gaps between each drops.......so, distance between each drop = 16/4 = 4
The height of each is to be calculated from the ground.......so ....for e.g. height of the 3rd drop = distance between the 1st drop and the ground + distance between the 1st drop and the 2nd drop + distance between the 2nd drop and the 3 rd drop = 0 + 4 + 4 = 8m
Height of the second drop = 4 m
Height of the third drop = 8 m
Height of the fourth drop = 12 m
Height of the fifth drop = 16 m
The above given heights are from the ground.
See....the case is....when the first drop starts falling, the fifth drop has reached the ground.......implies that there are 4 gaps between each drops.......so, distance between each drop = 16/4 = 4
The height of each is to be calculated from the ground.......so ....for e.g. height of the 3rd drop = distance between the 1st drop and the ground + distance between the 1st drop and the 2nd drop + distance between the 2nd drop and the 3 rd drop = 0 + 4 + 4 = 8m
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