Question

Due 24 jul



a car travels at 54 km/h for first 20 s, 36 km/h for next 30 s and finally 18 km/h for next 10 s. find its average speed

Answer 1

Hii..
Here is your answer..

Solution:-
Speed 1 =54km/h
$= > 54 \times \frac{5}{18} \\ = > 15 \: m \: per \: sec$
Time 1 =20 sec
So,
Distance=Speed ×Time
$= > 15 \times 20 \\ = > 300m$
Now,
Speed 2nd =36km/h
$= > 36 \times \frac{5}{18} \\ = > 10 \: m \: per \: sec$
Time 2nd =30sec
So,
Distance=Time × Speed
$= > 10 \times 30 \\ = > 300m$
Now,
Speed 3rd =18km/h
$= > 18 \times \frac{5}{18} \\ = > 5 \: m \: per \: sec$
Time 3rd =10 sec
So,
Distance=Speed ×Time
$= > 5 \times 10 \\ = > 50m$
Now,
Total Distance travelled=300+300+50
$= > 650m$
Total time =20+30+10
$= > 60sec$
We know that,
$average \: speed = \frac{total \: distance}{total \: time \: taken}$
$= > \frac{650}{60} \\ = > 10.84$

Hence,
Average speed is 10.84m/s

Hope it helps uh...✌️✌️✌️

Answer 2

Explanation:

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