Question

due to application of brakes decor comes to rwst in 5 seconds having initial velocity 10 minute per seconds find its retardation​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Retardation=2\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given: }} \\ \tt: \implies Initial \: velocity(u) = 10 \: m/s \\ \\ \tt: \implies 5ime(t) = 5 \: sec \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Acceleration(a) = ?$

• According to given question :

$\tt \circ \: Final \: velocity = 0 \: m/s \\ \\ \tt \circ \: Time = 5 \: sec \\ \\ \tt \circ \: Initial \: velocity = 10 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 0 = 10 + a \times 5 \\ \\ \tt: \implies - 10 = a \times 5 \\ \\ \tt: \implies a = \frac{ - 10}{5} \\ \\ \green{\tt: \implies a = - 2 \: m/{s}^{2} } \\ \\ \green{\tt \therefore Retardation \: is \: 2 \: m/{s}^{2} } \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{ \tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{ \tt \circ \: s = ut + \frac{1}{2} a{t}^{2} }$

Answer 2

$\tt{\huge{\orange {Hello!!! }}} B.Q$

QUESTION :

due to application of brakes decor comes to rwst in 5 seconds having initial velocity 10 minute per seconds find its retardation.

SOLUTION :

U = 10 m / s^2

U = 10 m / s^2V = 0 m / s^2

T = 5 Seconds.

According to First equation of motion :

V = u + at

=> 0 = 10 + 5a

=> a = -2 m/s^2

So the retardation of the vehicle is 2 m/s^2.

Other equations of motion :

V^2 = U^2 + 2 as

S = ut + 1/2 a t^2