Question

Due to applying forces upon a Toy car of weight 3.92 N, it starts to move with an acceleration 0.5m/s^2 on the floor where frictional force is 0.5 N
1. calculate the force acting upon the car
2. Will you get any Change in acceleration due to the frictional and Friction less floor? Explain mathematically​

Answer 1

Answer:1)1.96N

Explanation:1)Given:

m=3.92kg and a=0.5ms^-2.

Solution :

F=ma

F=3.92kg x 0.5ms^-2

F =1.96N.