Question

Due to some technical problems, a train started late by one hour from its starting point. The driver decided to increase the speed of the train by 100 km/h from its usual speed, to cover a journey of 1200 km in time. i) Find the usual speed of the train.​

Answer 1

Answer:

Let the original speed be 'x'

Original time taken (OT) = 1200/x

New time (NT) = 1200/x+100

New time (NT) = 1200/x+100According to the question

OT - NT = 1

1200/x - 1200/x+100 = 1

1200/(x+100) - 1200x/x²+100x = 1

1200x+120000 - 1200x/x²+100x = 1

120000 = x²+100x

x²+100x-120000 = 0

x²+400x-300x-120000 = 0

x(x+400) - 300(x+400) = 0

(x+400) (x-300) = 0

x = -400

x = 300

Speed cannot be negative.

Therefore, x= 300

The speed is 300 km/hr

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Answer 2

Answer:

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hru?

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