Question

Duivo we
Wing. (ALY 4)
(I) Two years ago my age was 4 1/2 times the age of my son.Six years ago, my age
was twice the square of the age of my son. What is the present age of my son?​

Answer 1

Step-by-step explanation:

let son age be x and the person ( my ) age be y

according to first condition

two years ago so substract 2 my age was so y equal to . 4 and half times son so 4.5 x

so equation is

y = 4.5x - 2. equation 1

according to second condition

y years ago so substract 6 my age was y is equal to . twice the square of son age so 2x square

so equation is

y = 2x² equation 2

equating 1 and 2 as LHS are equal

4.5x - 2 = 2x²

2x² - 4.5x + 2 = 0

x² - 2.25x + 1 = 0

this can be solved by quadratic method which is

m = - b ✓ b² - 4ac / 2a

where the

a = 1. b= 2.25 c = 1