Question

DULIU TULIDUI DULYVLERAVA
(22. Prove that the rectangle circumscribing a circle is a square​

Answer 1

AP=AS.....(1),BP=BQ....(2),CR=CQ....(3),DR=DS.....(4)(TANGENT FROM SAME POINT OUTSIDE CIRCLE)

BY ADDING THIS EQUATIONS

WE GET,

AP+BP+CR+DR=AS+DS+BQ+CQ

AB+CD=AD+BC

SO,

AB=CD,AD=BC(OPPOSITE SIDES OF RECTANGLE)

ANGLE A=ANGLE B=ANGLE C= ANGLE D=90 DEGREE(PROPERTY OF RECTANGLE)

SO,ABCD IS A SQUARE