Question

DUOTUL PIPOTON
A sample of calcium carbonate (CaCO,) has the following percentage composition: Ca 407,
C=12%;O=48%. If the law of constant proportions is true, then the weight of calcium in 4 g of a
sample of calcium carbonate from another source will be
(1) 0.016g
(2) 0.16 g
(3) 1.6 g
(4) 16 g
plz answer this question with correct explaination ​

Answer 1

calcium carbonate, from any source contains 40% calcium, so 4 g of calcium carbonate contain:

4: 100X40g = 1.6g of calcium

Here you go ❤️

Happy?

Answer 2

Answer:

1.6gm

Explanation:

in 100 gm CaCO3 40 gm Ca is present

then in 4 gm CaCO3 let it be x

x=4×40÷100

x=1.6gms

hope that help