Question

During a tennis match, a player hits the ball reaching a speed of
58 m/s. What is the average force exerted on the 0.057-kg tennis
ball by the player, assuming that the ball’s speed just after impact is
58 m/s and that the initial horizontal component of the velocity
before impact is negligible and that the ball remained in contact
with the racquet for 5.0 ms (milliseconds)?

Answer 1

Answer:

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Answer 2

661.2 N  is the average force exerted on the 0.057-kg tennis  ball by the player

Explanation:

F  = m dv/dt

m = 0.057 kg

dv =  58 m/s

dt =  5 ms = 5 * 10⁻³ s

F = 0.057 *  (58/ 5 * 10⁻³)

=> F = 57 * 58 / 5

=> F = 661.2 N

or v = u + at

=> 58 = 0  + a (5 *  10⁻³)

=> a = 58/ (5 *  10⁻³)

F = ma  =   0.057 *  (58/ 5 * 10⁻³) = 661.2 N

average force exerted on the 0.057-kg tennis  ball by the player,  = 661.2 N

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