Question

During an Army training session, 150 people are standing in a single line. If a person in the line is
chosen at random, what is the probability that his/her position lies between the 20th and the
40th
person?​

Answer 1

Answer:

19/150  or  0.1266......

Step-by-step explanation:

⇒40-20=20

⇒20-1   (since we need between 20th and 40th person we need to minus 1 )

⇒possible outcomes=19

⇒total outcomes=150

⇒possible outcome/total outcome

⇒19/150=0.1266....

Answer 2

During an Army training session, 150 people are standing in a single line. If a person in the line is chosen at random, 0.126 is the probability that his/her position lies between the 20th and the 40th person.

Given,

Number of people in line = 150

To find,

probability that position lies between the 20th and the 40th person = ?

Solution,

Positions between 20th to 40th = 19

Probability = $\frac{F.O}{T.O}$  (F.O = Favorable outcomes, T.O = Total outcomes)

F.O = Favorable outcomes = 19

T.O = Total outcomes = 150

$\frac{F.O}{T.O} = \frac{19}{150} = 0.126$

Therefore, during an Army training session, 150 people are standing in a single line. If a person in the line is chosen at random, 0.126 is the probability that his/her position lies between the 20th and the 40th person.