during an experiment a signal from a spaceship reached the ground station in 5 minutes what was the distance of the spaceship from the ground station? the signal Travels at the speed of light that is 3*10power8m/s.
I need this question answer with a bit explanation
Rajatkumarkhillar:
can u tell me ...that of which chapter this question belongs to....
chapter 8 motion
itna bda question toh nhi tha
it is there see page 102
in NCERT Book
ya that is another thing if you don't Know the ans
wait ...let think it again....meine apna answer nikal liya hai ...ek baar alag method se kar ke dekhta hun
hey...i had done my answer ...i don't know it is correct or not...if it is correct then i will explain it
the answer is 9×10to the power 10
thnxx shreya
Answers
Answered by
1
3 x 10 to the power 8 = dist./5
v = s/t
s = vt
= 3 x 10 power 8 x 5 x 60
= 900 x 10 power 8
= 3 x 3 x 10 power 2 x 10 power 8
= 9 x 10 to the power 10
v = s/t
s = vt
= 3 x 10 power 8 x 5 x 60
= 900 x 10 power 8
= 3 x 3 x 10 power 2 x 10 power 8
= 9 x 10 to the power 10
Answered by
1
hey .......here your answer
Speed= 3 × 10^8 m s−1
Time= 5 min = 5 × 60 = 300 secs.
Distance= Speed × Time
Distance= 3 × 10^8 m s−1 × 300 secs. = 9 × 10^power10 m
Speed= 3 × 10^8 m s−1
Time= 5 min = 5 × 60 = 300 secs.
Distance= Speed × Time
Distance= 3 × 10^8 m s−1 × 300 secs. = 9 × 10^power10 m
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