Math, asked by tylon293847, 3 months ago

During an experiment, a spinner landed on green 9 times, which resulted in an experimental probability of StartFraction 1 over 6 EndFraction. Mary said that there must have been 45 trials in the experiment. Why is Mary incorrect?
If there were 9 occurrences and 45 trials, the simplified experimental probability would be One-fifth, not StartFraction 1 over 6 EndFraction.
Mary multiplied the 9 occurrences by 6 instead of 5.
Mary mistakenly thought that StartFraction 1 over 6 EndFraction was the simplest form of StartFraction 9 over 45 EndFraction.
If there were 9 occurrences, the simplified experimental probability would be StartFraction 1 over 7 EndFraction, not StartFraction 1 over 6 EndFraction.

Answers

Answered by Anonymous
9

Step-by-step explanation:

What is the best explanation of how do you find the experimental probability of rolling a 3 to find the experimental probability of rolling a three write a ratio of the number of times three occurs to the total number of trials simplify if necessary to find the experimental probability of rolling a three write a ratio of the total?

Answered by hafsairfanalam
3

Answer:

I hope I have solved your problem

Step-by-step explanation:

it's because if there was 45 trials, and u landed on green 9 times...the resulting probability would be 9/45 which reduces to 1/5, not 1/6.

it's because if there was 45 trials, and u landed on green 9 times...the resulting probability would be 9/45 which reduces to 1/5, not 1/6.however, if there were 54 trials, and u landed on green 9 times...the resulting probability would be 9/54 which reduces to 1/6.

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