Question

during an experiment the students were asked to prepare a 10% solution of sugar in water ramesh dissolved 10 g of sugar in 100 g of water while suresh prepared it by dissolving 10g of sugar in water to make 100 g of the solution b) compare the masss % of two solutions
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Answer 1

Answer:

a) No, both are different.

b) Ramesh- 9.9%

   Sarika - 10%

Explanation:

According to the solution prepared by Ramesh,

Mass of sugar he took (Solute) = 10 g

Mass of water he took (Solvent) = 100 g

Thus Mass % of the solution =  

$\frac{mass \: of \: solute}{mass \: of \: solution} = \frac{10}{100} \times 100 \\ = \frac{100}{11} \\ = 9.9\%$

According to the solution prepared by Sarika,

Mass of sugar she took (Solute) = 10 g

Mass of Solution she took  = 100 g

Thus Mass % of the solution =

$\frac{mass \: of \: solute}{mass \: of \: solution} = \frac{10}{100} \times 100 \\ = 10\%$

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Answer 2

$answer.....$

$a)no \: both \: are \: different$

$b)ramesh \: is \: 99\%$

$sarika \: is \: 10\%$

$according \: to \: the \: solution \: prepared \: by \: ramesh$

$mass \: of \: sugar \:he \: took = 10g$

$mass \: of \: water \: he \: took = 100g$

$mass\% \: of \: the \: solution =$

$mass \: of \: solute \div mass \: of \: solution$

$= 10 \div 100 \times 100 = 99\%$

$according \: to \: the \: solution \: prepared \: by \: sarika$

$mass \: of \: sugar \: she \: took = 10$

$mass \: of \: solution \: she \: took = 100g$

$mass\% \: of \: the \: solution$

$mass \: of \: solute \div mass \: of \: solution$

$= 10 \div 100 \times 100 = 10\%$

$hope \: it \: will \: help \: u \: nanba$