Chemistry, asked by maisayantan8598, 10 months ago

During compression of a spring the work done is 10kJ and 2kJ escaped to the surroundings as heat. The change in internal energy, ∆U (in kJ) is:
(A) 8 (B) 12
(C) -12 (D) -8

Answers

Answered by Anonymous
0

Explanation:

During compression of a spring the work done is 10kJ and 2kJ escaped to the surroundings as heat. The change in internal energy, ∆U (in kJ) is:

(A) 8 (B) 12

(C) -1✓✓

(D) -8

Answered by 16shots
6

\huge\bold{-12}

Similar questions