Math, asked by AbhiACHU6617, 8 months ago

The locus of the centres of the circles, which touch the circle, x² + y² = 1 externally, also touch the y-axis and lie in the first quadrant is (A) x = √(1 + 2y), y ≥ 0 (B) y = √(1 + 4x), x ≥ 0 (C) x = √(1 + 4y), y ≥ 0 (D) y = √(1 + 2x), x ≥ 0

Answers

Answered by Anonymous
1

Step-by-step explanation:

The locus of the centres of the circles, which touch the circle, x² + y² = 1 externally, also touch the y-axis and lie in the first quadrant is (A) x = √(1 + 2y), y ≥ 0 (B) y = √(1 + 4x), x ≥ 0 (C) x = √(1 + 4y), y ≥ 0 (D) y = √(1 + 2x), x ≥ 0✓✓

Answered by 16shots
6

\huge\bold{(D)}

y= √(1+2x). x >0

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