Question

During electrolysis process of aqueous KCl, using inert electrodes, H2 is evolved at one elctrode and Cl2 is evolved at the other. The solution near the electrode at which H2 is evolved becomes basic as electrolysis proceeds. Which of the following reactions are applicable to the cathode ? Justify (5)
(a) 2H2O +2 e- ----> H2 + 2 OH-
(b) 2 H2O ----> O2 + 4 H+ + 4e-
(c) 2Cl- ----> Cl2 +2e-
(d) Cl2 + 2e- -----> 2Cl

Answer 1

The following reactions are applicable to the cathode:

2H₂O +2e⁻ → H₂ + 2OH⁻ (Option a)

• By the process of electrolysis, potassium chloride is separated into its constituent elements, that is, potassium metal and chlorine gas.
• Separate reactions occur at the cathode and the anode and they are termed as half equations.
• Reaction that occurs at the cathode is:

        2H₂O +2 e⁻ → H₂ + 2 OH-

• Reaction that occurs at the anode is:

        2Cl⁻ + 2e⁻ → Cl₂

       

Answer 2

HELLO DEAR,

ANSWER:-

(a) 2H2O +2 e- ----> H2 + 2 OH-

At cathode the reaction -

X^n+ + ne- ----------> X ( reduction half reaction)

Due to the electrolysis process KCl gets seperated into its constituent elements.

When potassium chloride is used

Electrolyte in electrolysis potassium bacon positive move to cathode and discharge thereafter reduction,vinyl chloride to go to anode and release as chlorine gas after oxidation in this way chlorine is produced as anode and potassium is discharged at cathode.

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THANKS.